Dominant B and recessive b
Cross between Heterozygous (Bb) parents
B
b
B
BB
bB
b
Bb
bb
Dominant B and recessive b
Cross between a Homozygous dominant (BB) parent and a Heterozygous (Bb) parent
B
B
B
BB
BB
b
Bb
Bb
Dihybrid crosses
A dihybrid cross with two hetrozygous parents
Gene 1: A-dominant, a-recessive
Gene 2: C-dominant, c-recessive
Parents are heterozygous for both genes
Parent 1: Genotype=AaCc
Parent 2: Genotype=AaCc
Gene 1 Gene 2
A C
A c
a C
a c
A C
AA CC
AA Cc
Aa CC
Aa Cc
A c
AA Cc
AA cc
Aa Cc
Aa cc
a C
Aa CC
Aa Cc
aa CC
aa Cc
a c
Aa Cc
Aa cc
aa Cc
aa cc
Thus in this case, the probablity of a child having
is:
A dihybrid cross with one hetrozygous parent and one homozygous recessive parent
Gene 1: A-dominant, a-recessive
Gene 2: C-dominant, c-recessive
Parent 1: Genotype=AaCc
Parent 2: Genotype=aacc
Gene 1 Gene 2
A C
A c
a C
a c
a c
Aa Cc
Aa cc
aa Cc
aa cc
a c
Aa Cc
Aa cc
aa Cc
aa cc
a c
Aa Cc
Aa cc
aa Cc
aa cc
a c
Aa Cc
Aa cc
aa Cc
aa cc
Thus in this case, the probablity of a child having
is:
A dihybrid test cross
Mendel's round, wrinkled, yellow, and green pea seeds
Gene 1: W-dominant: Wrinkled (wri) seeds, w-recessive: round (rou) seeds
Gene 2: G-dominant: Yellow (yel) seeds, g-recessive: green (gre) seeds
One homozygous recessive parent and one heterozygous or homozygous dominant parent
Parent 1: Genotype=wwgg Phenotype=round green seeds
Parent 2: Genotype=W?G? Phenotype=wrinkled yellow seeds
Gene 1 Gene 2
W G
W ?
? G
? ?
w g
Ww Gg
Ww g ?
w ? Gg
w ? g ?
w g
Ww Gg
Ww g ?
w ? Gg
w ? g ?
w g
Ww Gg
Ww g ?
w ? Gg
w ? g ?
w g
Ww Gg
Ww g ?
w ? Gg
w ? g ?
If you have 84 offspring from this cross and the offspring are
then the unknown parent's genotype is
Sex Chromosomes
Sex Linked Trait
On this page you have given answers of which were right.